(3x-10)=(1/4(8x+12))

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Solution for (3x-10)=(1/4(8x+12)) equation: 



(3x-10)=(1/4(8x+12))

We move all terms to the left:

(3x-10)-((1/4(8x+12)))=0



Domain of the equation: 4(8x+12)))!=0

x∈R



We get rid of parentheses

3x-((1/4(8x+12)))-10=0

We multiply all the terms by the denominator


3x*4(8x+12)))-((1-10*4(8x+12)))=0

Wy multiply elements

12x^2(8-40x(8=0

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