(3x-10)=1/4(8x+12)

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Solution for (3x-10)=1/4(8x+12) equation: 



(3x-10)=1/4(8x+12)

We move all terms to the left:

(3x-10)-(1/4(8x+12))=0



Domain of the equation: 4(8x+12))!=0

x∈R



We get rid of parentheses

3x-(1/4(8x+12))-10=0

We multiply all the terms by the denominator


3x*4(8x+12))-(1-10*4(8x+12))=0

Wy multiply elements

12x^2(8-40x(8=0

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