(3x-10)+(2x+20)=89

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Solution for (3x-10)+(2x+20)=89 equation: 



(3x-10)+(2x+20)=89

We move all terms to the left:

(3x-10)+(2x+20)-(89)=0

We get rid of parentheses

3x+2x-10+20-89=0

We add all the numbers together, and all the variables

5x-79=0

We move all terms containing x to the left, all other terms to the right

5x=79

x=79/5

x=15+4/5

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