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1/5x+8=110x+9.
We move all terms to the left:
1/5x+8-(110x+9.)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
1/5x-(110x+9)+8=0
We get rid of parentheses
1/5x-110x-9+8=0
We multiply all the terms by the denominator
-110x*5x-9*5x+8*5x+1=0
Wy multiply elements
-550x^2-45x+40x+1=0
We add all the numbers together, and all the variables
-550x^2-5x+1=0
a = -550; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·(-550)·1
Δ = 2225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2225}=\sqrt{25*89}=\sqrt{25}*\sqrt{89}=5\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{89}}{2*-550}=\frac{5-5\sqrt{89}}{-1100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{89}}{2*-550}=\frac{5+5\sqrt{89}}{-1100} $
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