(3x-1)/4=(2x+4)/5

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Solution for (3x-1)/4=(2x+4)/5 equation: 



(3x-1)/4=(2x+4)/5

We move all terms to the left:

(3x-1)/4-((2x+4)/5)=0

We calculate fractions


3x/()+(-((2x+4)*4)/()=0



We calculate terms in parentheses: +(-((2x+4)*4)/(), so:

-((2x+4)*4)/(

We multiply all the terms by the denominator


-((2x+4)*4)



We calculate terms in parentheses: -((2x+4)*4), so:

(2x+4)*4

We multiply parentheses

8x+16

Back to the equation:

-(8x+16)



We get rid of parentheses

-8x-16

Back to the equation:

+(-8x-16)



We get rid of parentheses

3x/()-8x-16=0

We multiply all the terms by the denominator


3x-8x*()-16*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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