23+4(j-3)-j=11

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Solution for 23+4(j-3)-j=11 equation: 



23+4(j-3)-j=11

We move all terms to the left:

23+4(j-3)-j-(11)=0

We add all the numbers together, and all the variables

-1j+4(j-3)+12=0

We multiply parentheses

-1j+4j-12+12=0

We add all the numbers together, and all the variables

3j=0

j=0/3

j=0

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