(3x-1)(5x)=(2x-3)(5x+4)

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Solution for (3x-1)(5x)=(2x-3)(5x+4) equation: 



(3x-1)(5x)=(2x-3)(5x+4)

We move all terms to the left:

(3x-1)(5x)-((2x-3)(5x+4))=0

We multiply parentheses

15x^2-5x-((2x-3)(5x+4))=0

We multiply parentheses ..

15x^2-((+10x^2+8x-15x-12))-5x=0



We calculate terms in parentheses: -((+10x^2+8x-15x-12)), so:

(+10x^2+8x-15x-12)

We get rid of parentheses

10x^2+8x-15x-12

We add all the numbers together, and all the variables

10x^2-7x-12

Back to the equation:

-(10x^2-7x-12)



We add all the numbers together, and all the variables

15x^2-5x-(10x^2-7x-12)=0

We get rid of parentheses

15x^2-10x^2-5x+7x+12=0

We add all the numbers together, and all the variables

5x^2+2x+12=0

a = 5; b = 2; c = +12;
Δ = b2-4ac
Δ = 22-4·5·12
Δ = -236
Delta is less than zero, so there is no solution for the equation

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