(2x-35)/15=(5x-11)/12

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Solution for (2x-35)/15=(5x-11)/12 equation: 



(2x-35)/15=(5x-11)/12

We move all terms to the left:

(2x-35)/15-((5x-11)/12)=0

We calculate fractions


2x/()+(-((5x-11)*15)/()=0



We calculate terms in parentheses: +(-((5x-11)*15)/(), so:

-((5x-11)*15)/(

We multiply all the terms by the denominator


-((5x-11)*15)



We calculate terms in parentheses: -((5x-11)*15), so:

(5x-11)*15

We multiply parentheses

75x-165

Back to the equation:

-(75x-165)



We get rid of parentheses

-75x+165

Back to the equation:

+(-75x+165)



We get rid of parentheses

2x/()-75x+165=0

We multiply all the terms by the denominator


2x-75x*()+165*()=0

We add all the numbers together, and all the variables

2x-75x*()=0

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