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(3x-1)(3x)=70
We move all terms to the left:
(3x-1)(3x)-(70)=0
We multiply parentheses
9x^2-3x-70=0
a = 9; b = -3; c = -70;
Δ = b2-4ac
Δ = -32-4·9·(-70)
Δ = 2529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2529}=\sqrt{9*281}=\sqrt{9}*\sqrt{281}=3\sqrt{281}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{281}}{2*9}=\frac{3-3\sqrt{281}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{281}}{2*9}=\frac{3+3\sqrt{281}}{18} $
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