(3x+8)+(3x+7)+(3x)=(3x)+(4x+1)

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Solution for (3x+8)+(3x+7)+(3x)=(3x)+(4x+1) equation: 



(3x+8)+(3x+7)+(3x)=(3x)+(4x+1)

We move all terms to the left:

(3x+8)+(3x+7)+(3x)-((3x)+(4x+1))=0

We add all the numbers together, and all the variables

3x+(3x+8)+(3x+7)-(3x+(4x+1))=0

We get rid of parentheses

3x+3x+3x-(3x+(4x+1))+8+7=0



We calculate terms in parentheses: -(3x+(4x+1)), so:

3x+(4x+1)

We get rid of parentheses

3x+4x+1

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We add all the numbers together, and all the variables

9x-(7x+1)+15=0

We get rid of parentheses

9x-7x-1+15=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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