4(m-2)+3(4m-4)=15(m-1)-7

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Solution for 4(m-2)+3(4m-4)=15(m-1)-7 equation: 



4(m-2)+3(4m-4)=15(m-1)-7

We move all terms to the left:

4(m-2)+3(4m-4)-(15(m-1)-7)=0

We multiply parentheses

4m+12m-(15(m-1)-7)-8-12=0



We calculate terms in parentheses: -(15(m-1)-7), so:

15(m-1)-7

We multiply parentheses

15m-15-7

We add all the numbers together, and all the variables

15m-22

Back to the equation:

-(15m-22)



We add all the numbers together, and all the variables

16m-(15m-22)-20=0

We get rid of parentheses

16m-15m+22-20=0

We add all the numbers together, and all the variables

m+2=0

We move all terms containing m to the left, all other terms to the right

m=-2

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