(3x+8)+(3x+7)+(3x)=(3x)+(3x)+(4x+3)

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Solution for (3x+8)+(3x+7)+(3x)=(3x)+(3x)+(4x+3) equation: 



(3x+8)+(3x+7)+(3x)=(3x)+(3x)+(4x+3)

We move all terms to the left:

(3x+8)+(3x+7)+(3x)-((3x)+(3x)+(4x+3))=0

We add all the numbers together, and all the variables

3x+(3x+8)+(3x+7)-(3x+3x+(4x+3))=0

We get rid of parentheses

3x+3x+3x-(3x+3x+(4x+3))+8+7=0



We calculate terms in parentheses: -(3x+3x+(4x+3)), so:

3x+3x+(4x+3)

We add all the numbers together, and all the variables

6x+(4x+3)

We get rid of parentheses

6x+4x+3

We add all the numbers together, and all the variables

10x+3

Back to the equation:

-(10x+3)



We add all the numbers together, and all the variables

9x-(10x+3)+15=0

We get rid of parentheses

9x-10x-3+15=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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