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(3x+8)+(2x-5)=53
We move all terms to the left:
(3x+8)+(2x-5)-(53)=0
We get rid of parentheses
3x+2x+8-5-53=0
We add all the numbers together, and all the variables
5x-50=0
We move all terms containing x to the left, all other terms to the right
5x=50
x=50/5
x=10
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