4(3x-4)+30=2(x-20)+10

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Solution for 4(3x-4)+30=2(x-20)+10 equation: 



4(3x-4)+30=2(x-20)+10

We move all terms to the left:

4(3x-4)+30-(2(x-20)+10)=0

We multiply parentheses

12x-(2(x-20)+10)-16+30=0



We calculate terms in parentheses: -(2(x-20)+10), so:

2(x-20)+10

We multiply parentheses

2x-40+10

We add all the numbers together, and all the variables

2x-30

Back to the equation:

-(2x-30)



We add all the numbers together, and all the variables

12x-(2x-30)+14=0

We get rid of parentheses

12x-2x+30+14=0

We add all the numbers together, and all the variables

10x+44=0

We move all terms containing x to the left, all other terms to the right

10x=-44

x=-44/10

x=-4+2/5

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