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(3x+8)(8x+3)=0
We multiply parentheses ..
(+24x^2+9x+64x+24)=0
We get rid of parentheses
24x^2+9x+64x+24=0
We add all the numbers together, and all the variables
24x^2+73x+24=0
a = 24; b = 73; c = +24;
Δ = b2-4ac
Δ = 732-4·24·24
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-55}{2*24}=\frac{-128}{48} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+55}{2*24}=\frac{-18}{48} =-3/8 $
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