(3x+7)/2=(1+x)/3

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Solution for (3x+7)/2=(1+x)/3 equation: 



(3x+7)/2=(1+x)/3

We move all terms to the left:

(3x+7)/2-((1+x)/3)=0

We add all the numbers together, and all the variables

(3x+7)/2-((x+1)/3)=0

We calculate fractions


3x/()+(-((x+1)*2)/()=0



We calculate terms in parentheses: +(-((x+1)*2)/(), so:

-((x+1)*2)/(

We multiply all the terms by the denominator


-((x+1)*2)



We calculate terms in parentheses: -((x+1)*2), so:

(x+1)*2

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We get rid of parentheses

-2x-2

Back to the equation:

+(-2x-2)



We get rid of parentheses

3x/()-2x-2=0

We multiply all the terms by the denominator


3x-2x*()-2*()=0

We add all the numbers together, and all the variables

3x-2x*()=0

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