(2n-3)+(3n-2)+33=180

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Solution for (2n-3)+(3n-2)+33=180 equation: 



(2n-3)+(3n-2)+33=180

We move all terms to the left:

(2n-3)+(3n-2)+33-(180)=0

We add all the numbers together, and all the variables

(2n-3)+(3n-2)-147=0

We get rid of parentheses

2n+3n-3-2-147=0

We add all the numbers together, and all the variables

5n-152=0

We move all terms containing n to the left, all other terms to the right

5n=152

n=152/5

n=30+2/5

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