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(3x+7)(7x-8)=14
We move all terms to the left:
(3x+7)(7x-8)-(14)=0
We multiply parentheses ..
(+21x^2-24x+49x-56)-14=0
We get rid of parentheses
21x^2-24x+49x-56-14=0
We add all the numbers together, and all the variables
21x^2+25x-70=0
a = 21; b = 25; c = -70;
Δ = b2-4ac
Δ = 252-4·21·(-70)
Δ = 6505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{6505}}{2*21}=\frac{-25-\sqrt{6505}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{6505}}{2*21}=\frac{-25+\sqrt{6505}}{42} $
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