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(3x+7)(2x-8)=0
We multiply parentheses ..
(+6x^2-24x+14x-56)=0
We get rid of parentheses
6x^2-24x+14x-56=0
We add all the numbers together, and all the variables
6x^2-10x-56=0
a = 6; b = -10; c = -56;
Δ = b2-4ac
Δ = -102-4·6·(-56)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-38}{2*6}=\frac{-28}{12} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+38}{2*6}=\frac{48}{12} =4 $
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