(3x+65)=(2x+82)

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Solution for (3x+65)=(2x+82) equation: 



(3x+65)=(2x+82)

We move all terms to the left:

(3x+65)-((2x+82))=0

We get rid of parentheses

3x-((2x+82))+65=0



We calculate terms in parentheses: -((2x+82)), so:

(2x+82)

We get rid of parentheses

2x+82

Back to the equation:

-(2x+82)



We get rid of parentheses

3x-2x-82+65=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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