-(12+4c)=6c-(19+13)

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Solution for -(12+4c)=6c-(19+13) equation: 



-(12+4c)=6c-(19+13)

We move all terms to the left:

-(12+4c)-(6c-(19+13))=0

We add all the numbers together, and all the variables

-(4c+12)-(6c-32)=0

We get rid of parentheses

-4c-6c-12+32=0

We add all the numbers together, and all the variables

-10c+20=0

We move all terms containing c to the left, all other terms to the right

-10c=-20

c=-20/-10

c=+2

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