(3x+5)=(40-2x)

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Solution for (3x+5)=(40-2x) equation: 



(3x+5)=(40-2x)

We move all terms to the left:

(3x+5)-((40-2x))=0

We add all the numbers together, and all the variables

(3x+5)-((-2x+40))=0

We get rid of parentheses

3x-((-2x+40))+5=0



We calculate terms in parentheses: -((-2x+40)), so:

(-2x+40)

We get rid of parentheses

-2x+40

Back to the equation:

-(-2x+40)



We get rid of parentheses

3x+2x-40+5=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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