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(3x+5)(21x+3)=176
We move all terms to the left:
(3x+5)(21x+3)-(176)=0
We multiply parentheses ..
(+63x^2+9x+105x+15)-176=0
We get rid of parentheses
63x^2+9x+105x+15-176=0
We add all the numbers together, and all the variables
63x^2+114x-161=0
a = 63; b = 114; c = -161;
Δ = b2-4ac
Δ = 1142-4·63·(-161)
Δ = 53568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{53568}=\sqrt{576*93}=\sqrt{576}*\sqrt{93}=24\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(114)-24\sqrt{93}}{2*63}=\frac{-114-24\sqrt{93}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(114)+24\sqrt{93}}{2*63}=\frac{-114+24\sqrt{93}}{126} $
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