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2v-(-5-6v)=5(1+8v)
We move all terms to the left:
2v-(-5-6v)-(5(1+8v))=0
We add all the numbers together, and all the variables
2v-(-6v-5)-(5(8v+1))=0
We get rid of parentheses
2v+6v-(5(8v+1))+5=0
We calculate terms in parentheses: -(5(8v+1)), so:We add all the numbers together, and all the variables
5(8v+1)
We multiply parentheses
40v+5
Back to the equation:
-(40v+5)
8v-(40v+5)+5=0
We get rid of parentheses
8v-40v-5+5=0
We add all the numbers together, and all the variables
-32v=0
v=0/-32
v=0
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