(3x+4)+(6x)=112

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Solution for (3x+4)+(6x)=112 equation:



(3x+4)+(6x)=112
We move all terms to the left:
(3x+4)+(6x)-(112)=0
We add all the numbers together, and all the variables
6x+(3x+4)-112=0
We get rid of parentheses
6x+3x+4-112=0
We add all the numbers together, and all the variables
9x-108=0
We move all terms containing x to the left, all other terms to the right
9x=108
x=108/9
x=12

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