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2(x+2)=5(3x-5)
We move all terms to the left:
2(x+2)-(5(3x-5))=0
We multiply parentheses
2x-(5(3x-5))+4=0
We calculate terms in parentheses: -(5(3x-5)), so:We get rid of parentheses
5(3x-5)
We multiply parentheses
15x-25
Back to the equation:
-(15x-25)
2x-15x+25+4=0
We add all the numbers together, and all the variables
-13x+29=0
We move all terms containing x to the left, all other terms to the right
-13x=-29
x=-29/-13
x=2+3/13
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