(3x+4)(3x+4)=(7(3x+4)

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Solution for (3x+4)(3x+4)=(7(3x+4) equation: 



(3x+4)(3x+4)=(7(3x+4)

We move all terms to the left:

(3x+4)(3x+4)-((7(3x+4))=0

We multiply parentheses ..

(+9x^2+12x+12x+16)-((7(3x+4))=0



We calculate terms in parentheses: -((7(3x+4)), so:

(7(3x+4)



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7(3x+4





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7(3x+4





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7(3x+4





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7(3x+4





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7(3x+4





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7(3x+4





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7(3x+4





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7(3x+4





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7(3x+4





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7(3x+4





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We get rid of parentheses

9x^2+12x+12x-((7(3x+4))+16=0

We add all the numbers together, and all the variables

9x^2+24x-((7(3x+4))+16=0

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