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5(2x-4)+1=3(x-5)
We move all terms to the left:
5(2x-4)+1-(3(x-5))=0
We multiply parentheses
10x-(3(x-5))-20+1=0
We calculate terms in parentheses: -(3(x-5)), so:We add all the numbers together, and all the variables
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
10x-(3x-15)-19=0
We get rid of parentheses
10x-3x+15-19=0
We add all the numbers together, and all the variables
7x-4=0
We move all terms containing x to the left, all other terms to the right
7x=4
x=4/7
x=4/7
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