(3x+3)+(42x+42)=6

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Solution for (3x+3)+(42x+42)=6 equation: 



(3x+3)+(42x+42)=6

We move all terms to the left:

(3x+3)+(42x+42)-(6)=0

We get rid of parentheses

3x+42x+3+42-6=0

We add all the numbers together, and all the variables

45x+39=0

We move all terms containing x to the left, all other terms to the right

45x=-39

x=-39/45

x=-13/15

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