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9x^2+38x+8=0
a = 9; b = 38; c = +8;
Δ = b2-4ac
Δ = 382-4·9·8
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-34}{2*9}=\frac{-72}{18} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+34}{2*9}=\frac{-4}{18} =-2/9 $
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