(3x+23)=(2x+16)+(x+7)

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Solution for (3x+23)=(2x+16)+(x+7) equation: 



(3x+23)=(2x+16)+(x+7)

We move all terms to the left:

(3x+23)-((2x+16)+(x+7))=0

We get rid of parentheses

3x-((2x+16)+(x+7))+23=0



We calculate terms in parentheses: -((2x+16)+(x+7)), so:

(2x+16)+(x+7)

We get rid of parentheses

2x+x+16+7

We add all the numbers together, and all the variables

3x+23

Back to the equation:

-(3x+23)



We get rid of parentheses

3x-3x-23+23=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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