3(n+3)=9n-3(n-3)

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Solution for 3(n+3)=9n-3(n-3) equation:



3(n+3)=9n-3(n-3)
We move all terms to the left:
3(n+3)-(9n-3(n-3))=0
We multiply parentheses
3n-(9n-3(n-3))+9=0
We calculate terms in parentheses: -(9n-3(n-3)), so:
9n-3(n-3)
We multiply parentheses
9n-3n+9
We add all the numbers together, and all the variables
6n+9
Back to the equation:
-(6n+9)
We get rid of parentheses
3n-6n-9+9=0
We add all the numbers together, and all the variables
-3n=0
n=0/-3
n=0

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