(3x+20)=(5x-80)

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Solution for (3x+20)=(5x-80) equation:



(3x+20)=(5x-80)
We move all terms to the left:
(3x+20)-((5x-80))=0
We get rid of parentheses
3x-((5x-80))+20=0
We calculate terms in parentheses: -((5x-80)), so:
(5x-80)
We get rid of parentheses
5x-80
Back to the equation:
-(5x-80)
We get rid of parentheses
3x-5x+80+20=0
We add all the numbers together, and all the variables
-2x+100=0
We move all terms containing x to the left, all other terms to the right
-2x=-100
x=-100/-2
x=+50

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