(3x+2/5)=31

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Solution for (3x+2/5)=31 equation:



(3x+2/5)=31
We move all terms to the left:
(3x+2/5)-(31)=0
We add all the numbers together, and all the variables
(+3x+2/5)-31=0
We get rid of parentheses
3x-31+2/5=0
We multiply all the terms by the denominator
3x*5+2-31*5=0
We add all the numbers together, and all the variables
3x*5-153=0
Wy multiply elements
15x-153=0
We move all terms containing x to the left, all other terms to the right
15x=153
x=153/15
x=10+1/5

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