(3x+2)x+1)=3x2+17

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Solution for (3x+2)x+1)=3x2+17 equation: 



(3x+2)x+1)=3x^2+17

We move all terms to the left:

(3x+2)x+1)-(3x^2+17)=0

We add all the numbers together, and all the variables

(3x+2)x+1)-(3x^2=0

We multiply parentheses

3x^2+2x+1)-(3x^2=0

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