3(x+2)=9-3(x-1)

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Solution for 3(x+2)=9-3(x-1) equation:



3(x+2)=9-3(x-1)
We move all terms to the left:
3(x+2)-(9-3(x-1))=0
We multiply parentheses
3x-(9-3(x-1))+6=0
We calculate terms in parentheses: -(9-3(x-1)), so:
9-3(x-1)
determiningTheFunctionDomain -3(x-1)+9
We multiply parentheses
-3x+3+9
We add all the numbers together, and all the variables
-3x+12
Back to the equation:
-(-3x+12)
We get rid of parentheses
3x+3x-12+6=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1

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