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(3x+2)=(2x+13)/3
We move all terms to the left:
(3x+2)-((2x+13)/3)=0
We get rid of parentheses
3x-((2x+13)/3)+2=0
We multiply all the terms by the denominator
3x*3)-((2x+13)+2*3)=0
We add all the numbers together, and all the variables
3x*3)-((2x+13)=0
Wy multiply elements
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{18}=0$
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