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3(2x-1)-5(3-2x)=x-3
We move all terms to the left:
3(2x-1)-5(3-2x)-(x-3)=0
We add all the numbers together, and all the variables
3(2x-1)-5(-2x+3)-(x-3)=0
We multiply parentheses
6x+10x-(x-3)-3-15=0
We get rid of parentheses
6x+10x-x+3-3-15=0
We add all the numbers together, and all the variables
15x-15=0
We move all terms containing x to the left, all other terms to the right
15x=15
x=15/15
x=1
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