(3x+2)2=(2x-3)-3

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Solution for (3x+2)2=(2x-3)-3 equation: 



(3x+2)2=(2x-3)-3

We move all terms to the left:

(3x+2)2-((2x-3)-3)=0

We multiply parentheses

6x-((2x-3)-3)+4=0



We calculate terms in parentheses: -((2x-3)-3), so:

(2x-3)-3

We get rid of parentheses

2x-3-3

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

6x-2x+6+4=0

We add all the numbers together, and all the variables

4x+10=0

We move all terms containing x to the left, all other terms to the right

4x=-10

x=-10/4

x=-2+1/2

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