(3x+2)/4=(8x-1)/5

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Solution for (3x+2)/4=(8x-1)/5 equation: 



(3x+2)/4=(8x-1)/5

We move all terms to the left:

(3x+2)/4-((8x-1)/5)=0

We calculate fractions


3x/()+(-((8x-1)*4)/()=0



We calculate terms in parentheses: +(-((8x-1)*4)/(), so:

-((8x-1)*4)/(

We multiply all the terms by the denominator


-((8x-1)*4)



We calculate terms in parentheses: -((8x-1)*4), so:

(8x-1)*4

We multiply parentheses

32x-4

Back to the equation:

-(32x-4)



We get rid of parentheses

-32x+4

Back to the equation:

+(-32x+4)



We get rid of parentheses

3x/()-32x+4=0

We multiply all the terms by the denominator


3x-32x*()+4*()=0

We add all the numbers together, and all the variables

3x-32x*()=0

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