(3x+2)+4(2x-1)=5(x-2)

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Solution for (3x+2)+4(2x-1)=5(x-2) equation: 



(3x+2)+4(2x-1)=5(x-2)

We move all terms to the left:

(3x+2)+4(2x-1)-(5(x-2))=0

We multiply parentheses

(3x+2)+8x-(5(x-2))-4=0

We get rid of parentheses

3x+8x-(5(x-2))+2-4=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

11x-(5x-10)-2=0

We get rid of parentheses

11x-5x+10-2=0

We add all the numbers together, and all the variables

6x+8=0

We move all terms containing x to the left, all other terms to the right

6x=-8

x=-8/6

x=-1+1/3

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