(3x+2)*(2x+9)-(x+2)*(6x+1)=(x+1)-(x-6)

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Solution for (3x+2)*(2x+9)-(x+2)*(6x+1)=(x+1)-(x-6) equation: 



(3x+2)(2x+9)-(x+2)(6x+1)=(x+1)-(x-6)

We move all terms to the left:

(3x+2)(2x+9)-(x+2)(6x+1)-((x+1)-(x-6))=0

We multiply parentheses ..

(+6x^2+27x+4x+18)-(x+2)(6x+1)-((x+1)-(x-6))=0



We calculate terms in parentheses: -((x+1)-(x-6)), so:

(x+1)-(x-6)

We get rid of parentheses

x-x+1+6

We add all the numbers together, and all the variables

7

Back to the equation:

-(7)



We get rid of parentheses

6x^2+27x+4x-(x+2)(6x+1)+18-7=0

We multiply parentheses ..

6x^2-(+6x^2+x+12x+2)+27x+4x+18-7=0

We add all the numbers together, and all the variables

6x^2-(+6x^2+x+12x+2)+31x+11=0

We get rid of parentheses

6x^2-6x^2-x-12x+31x-2+11=0

We add all the numbers together, and all the variables

18x+9=0

We move all terms containing x to the left, all other terms to the right

18x=-9

x=-9/18

x=-1/2

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