(x+2)*(x+3)-(x+2)*(x+5)=6

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Solution for (x+2)*(x+3)-(x+2)*(x+5)=6 equation: 



(x+2)(x+3)-(x+2)(x+5)=6

We move all terms to the left:

(x+2)(x+3)-(x+2)(x+5)-(6)=0

We multiply parentheses ..

(+x^2+3x+2x+6)-(x+2)(x+5)-6=0

We get rid of parentheses

x^2+3x+2x-(x+2)(x+5)+6-6=0

We multiply parentheses ..

x^2-(+x^2+5x+2x+10)+3x+2x+6-6=0

We add all the numbers together, and all the variables

x^2-(+x^2+5x+2x+10)+5x=0

We get rid of parentheses

x^2-x^2-5x-2x+5x-10=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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