(3x+2)(9x-3)=0

Solution for (3x+2)(9x-3)=0 equation:

(3x+2)(9x-3)=0

We multiply parentheses ..

(+27x^2-9x+18x-6)=0

We get rid of parentheses

27x^2-9x+18x-6=0

We add all the numbers together, and all the variables

27x^2+9x-6=0

a = 27; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·27·(-6)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-27}{2*27}=\frac{-36}{54}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+27}{2*27}=\frac{18}{54}
=1/3
$