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3x+5(3x-4)=-4(6x-3)+10
We move all terms to the left:
3x+5(3x-4)-(-4(6x-3)+10)=0
We multiply parentheses
3x+15x-(-4(6x-3)+10)-20=0
We calculate terms in parentheses: -(-4(6x-3)+10), so:We add all the numbers together, and all the variables
-4(6x-3)+10
We multiply parentheses
-24x+12+10
We add all the numbers together, and all the variables
-24x+22
Back to the equation:
-(-24x+22)
18x-(-24x+22)-20=0
We get rid of parentheses
18x+24x-22-20=0
We add all the numbers together, and all the variables
42x-42=0
We move all terms containing x to the left, all other terms to the right
42x=42
x=42/42
x=1
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