(3x+2)(2+2x)=6x+6x2+4+4x=6x2+10x+4

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Solution for (3x+2)(2+2x)=6x+6x2+4+4x=6x2+10x+4 equation:



(3x+2)(2+2x)=6x+6x^2+4+4x=6x^2+10x+4
We move all terms to the left:
(3x+2)(2+2x)-(6x+6x^2+4+4x)=0
We add all the numbers together, and all the variables
-(6x+6x^2+4+4x)+(3x+2)(2x+2)=0
We get rid of parentheses
-6x^2-6x-4x+(3x+2)(2x+2)-4=0
We multiply parentheses ..
-6x^2+(+6x^2+6x+4x+4)-6x-4x-4=0
We add all the numbers together, and all the variables
-6x^2+(+6x^2+6x+4x+4)-10x-4=0
We get rid of parentheses
-6x^2+6x^2+6x+4x-10x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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