(x+1)(3x-2)=(3x-3)(x+2)

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Solution for (x+1)(3x-2)=(3x-3)(x+2) equation: 



(x+1)(3x-2)=(3x-3)(x+2)

We move all terms to the left:

(x+1)(3x-2)-((3x-3)(x+2))=0

We multiply parentheses ..

(+3x^2-2x+3x-2)-((3x-3)(x+2))=0



We calculate terms in parentheses: -((3x-3)(x+2)), so:

(3x-3)(x+2)

We multiply parentheses ..

(+3x^2+6x-3x-6)

We get rid of parentheses

3x^2+6x-3x-6

We add all the numbers together, and all the variables

3x^2+3x-6

Back to the equation:

-(3x^2+3x-6)



We get rid of parentheses

3x^2-3x^2-2x+3x-3x-2+6=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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