(3x+19)+(10x-1)=(3x+4)

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Solution for (3x+19)+(10x-1)=(3x+4) equation: 



(3x+19)+(10x-1)=(3x+4)

We move all terms to the left:

(3x+19)+(10x-1)-((3x+4))=0

We get rid of parentheses

3x+10x-((3x+4))+19-1=0



We calculate terms in parentheses: -((3x+4)), so:

(3x+4)

We get rid of parentheses

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

13x-(3x+4)+18=0

We get rid of parentheses

13x-3x-4+18=0

We add all the numbers together, and all the variables

10x+14=0

We move all terms containing x to the left, all other terms to the right

10x=-14

x=-14/10

x=-1+2/5

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