(3x+13)=(8x-6)+(3x+5)

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Solution for (3x+13)=(8x-6)+(3x+5) equation: 



(3x+13)=(8x-6)+(3x+5)

We move all terms to the left:

(3x+13)-((8x-6)+(3x+5))=0

We get rid of parentheses

3x-((8x-6)+(3x+5))+13=0



We calculate terms in parentheses: -((8x-6)+(3x+5)), so:

(8x-6)+(3x+5)

We get rid of parentheses

8x+3x-6+5

We add all the numbers together, and all the variables

11x-1

Back to the equation:

-(11x-1)



We get rid of parentheses

3x-11x+1+13=0

We add all the numbers together, and all the variables

-8x+14=0

We move all terms containing x to the left, all other terms to the right

-8x=-14

x=-14/-8

x=1+3/4

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