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4(2x+3)-7=3(x-5)
We move all terms to the left:
4(2x+3)-7-(3(x-5))=0
We multiply parentheses
8x-(3(x-5))+12-7=0
We calculate terms in parentheses: -(3(x-5)), so:We add all the numbers together, and all the variables
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
8x-(3x-15)+5=0
We get rid of parentheses
8x-3x+15+5=0
We add all the numbers together, and all the variables
5x+20=0
We move all terms containing x to the left, all other terms to the right
5x=-20
x=-20/5
x=-4
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